Comments on: The Clarkkkkson vs. the xkcd Number

By: Shiva Ra

Shiva Ra — Sun, 25 Dec 2011 17:55:58 +0000

==udqbpn[sigma]1/x

By: Shiva Ra

Shiva Ra — Sun, 25 Dec 2011 17:54:56 +0000

udqbpn = largest non infinite number

By: ST

ST — Wed, 09 Nov 2011 03:18:34 +0000

What about numbers related to the Goodstein sequences?

(e.g. J(k) := number of steps it takes for the Goodstein sequence of 100 to go down to 0; then define S(n,k) := J(J(…(J(k))…)) (J repeated n times). BIG NUMBER:

J(100, 100)
)

By: Jacob

Jacob — Mon, 04 Jul 2011 16:51:44 +0000

hmm…. i’m pretty sure TREE(xkcd) would dwarf any number here, despite it’s ease in notation (go here: http://en.wikipedia.org/wiki/Kruskal%27s_tree_theorem for more on the TREE function)

Seeing as TREE(3) already dwarfs Graham’s number likely more then Graham’s number dwarfs googolplex, I’m pretty sure TREE(xkcd) would be enough to dwarf all the other numbers here, probably including BB(xkcd). not sure about how one would go about proving this though…

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By: Chuck Dvd

Chuck Dvd — Tue, 22 Feb 2011 22:47:57 +0000

I not sure I quite follow your post?? would you mind elaborating more?

By: izmir escort

izmir escort — Mon, 20 Dec 2010 22:04:32 +0000

That would be the Busy Beaver, to the order of the Busy Beaver function of Graham’s number, function of Ackerman’s function given two xkcd numbers.

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